Diagram 3 shows a composite solid, formed by joining a half m-cylinder with a right prism. ABKJ is the cross - section of the right prism. MK is the diameter of the half - cylinder
Given BK 28 cm, AJ = 14 and AE = 20 cm, The volume of the composite solid is 17000 cm³
Using
[tex]\pi = \frac{22}{7} [/tex]
calculate the value of h
pls help me answer this 
Given BK 28 cm, AJ = 14 and AE = 20 cm, The volume of the composite solid is 17000 cm³
Using
[tex]\pi = \frac{22}{7} [/tex]
calculate the value of h
pls help me answer this
If you think about composite solid id 17000 cm³, it means that is a combined between half cylinder and trapezium prism. It means in math model:
Volume of half cylinder + volume trapezium prism = 17.000
1/2 π r² t + [tex](\frac{(KB + JA) * BA}{2})[/tex] = 17.000
(Half in volume of half cylinder because that solid is really half not full cylinder)
1/2 * 3,14 * 10 * 10 * 28 + [tex](\frac{(28 + 14) * h}{2})[/tex] = 17.000
(Remember 10 from where? 10 is from 20 that required as radius of a half circle)
(Use a 3,14 to make a solvable result)
1/2 * 314 * 28 + [tex](\frac{42 * h}{2})[/tex] = 17.000
4396 + 21h = 17.000
21h = 17.000 - 4396
21h = 12604
h = 12604 : 21
h = 600,19 cm
So the value of h is 600,19 cm.
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